250=5x^2+30

Solution for 250=5x^2+30 equation:

250=5x^2+30

We move all terms to the left:

250-(5x^2+30)=0

We get rid of parentheses

-5x^2-30+250=0

We add all the numbers together, and all the variables

-5x^2+220=0

a = -5; b = 0; c = +220;
Δ = b2-4ac
Δ = 02-4·(-5)·220
Δ = 4400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4400}=\sqrt{400*11}=\sqrt{400}*\sqrt{11}=20\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{11}}{2*-5}=\frac{0-20\sqrt{11}}{-10}
=-\frac{20\sqrt{11}}{-10}
=-\frac{2\sqrt{11}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{11}}{2*-5}=\frac{0+20\sqrt{11}}{-10}
=\frac{20\sqrt{11}}{-10}
=\frac{2\sqrt{11}}{-1}
$